Super! I didin't think of using the *invert* function. That makes me a breeze Sunday Evening and I hope yours too. Frank

Hi Everybody   Use this Algorithm or Regex you call it:  (\S+\s+){0,2}\d{5} And this address: Mitnick, John and Julia (-Wimbledon) Wallstreet 355 55742 New York (888) 932 21 78  Surname, given name (-maiden name) street street no ZIP City Telephone no. This will result in  Wallstreet 355 55742 , exactly, extracting the ...

I'm working with Exchange 2007, which support regex expressions for filtering messages.  The majority of spam is sent from zombies that are most often on computers with dynamic IP address.  So if you look at the message header you will see something like the following examples: Received: from ...

Thanks!  I had some issues with the regex provided, but after further tweaking i got the final working solution. Here it is.. regex: \b\d+((?(?=[a-z])[a-z]))\s+(\b\w+\b\s+){1,3}(road|street) This will now work with: "6A XYZ COURT 1A CASTLE PEAK ROAD HONG KONG" "6 XYZ COURT 1 CASTLE PEAK ROAD HONG KONG" "6A XYZ COURT ...