Hi, given a string like "ProductA 1 Product B 1 2 3 ProductC 10 20 50" I need to obtain a list of products and a list of corresponding numbers related to each product.

The first list is easy to obtain:

s = "ProductA 1 Product B 1 2 3 ProductC 10 20 50"

p = re.compile(u"[a-zA-Z]+")

p.findall(s)

["ProductA", "ProductB", "ProductC"]

Now the second list should be done this way:

["1", "1 2 3", "10 20 50"]

I tried using this regex but it didn't work: (\s+\d+\s*)+ because findall returns [' 1 ', ' 1 ', ' 3 ', ' 10 ', ' 30'] which is totally unuseful to me. I also tried to change regex to (\s+\d+\s*)+? which enables greedy, but still wrong result.

Do you have any hint... or a solution? ;)

Thanks!

Take the same pattern you used to create your first list and perform a regex split against the original string to create the second list.

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Michael

"In theory, theory and practice are the same. In practice, they are not."
Albert Einstein

Of course, thanks a lot for you answer, this did the trick:

p = [item.strip().split() for item in p.split(s) if item]

that gives exactly what I need:

[['1'], ['1', '2', '3'], ['10', '20', '50']]