Hi,

 

I need to have a regex that looks for any digit before and after the char / 

 

for example This is my string1/232

 

I need to be able to extract 1/232

 

I am coding on java.

 

Any help will be appreciated.

 

I can probably just split on "/" and then for back and forth until next char is no digit, but I was wondering if there is something better that regex can offer.

 

Thanks

I don't know how Java rolls but as long as your delimiter(php is most often /, I use the most) is different you shouldn't have any problems else you'll need to escape it (php \/) and have your character class on either side of it with proper repetition (one or more or fixed)

forgot to add group your character classes since you want to extract and you'll have \1 and \2

Try something like:

(\d+)/(\d+)

as the pattern. The digit characters before the "/" will be in match group #1 and those after will be in match group #2.

As jewbacca mentioned, the "/" character is often used as a pattern delimiter so there are 2 options: either use something else as the pattern delimiter or escape the "/".

Therefore the line might look something like:

line =~ #(\d+)/(\d+)#;

or

line =~ /(\d+)\/(\d+)/;

(I don't use java so the syntax might not be 100% but you should get the idea).

Susan

Thank you very much this does help. I will polish it up and will post my code as soon I am done.

 

Thanks