I have been bashing my head trying to find a way to do this.

 I am cleaning out some text files and most of the time a simple "Find>Replace" method works but I am trying to remove somthing like this:

  The text file would look like:

Hello my name is Dave [1], I am from California [2] an I like fishing [3].

 I would like to strip out all of the numbers in brackets (including the brackets themselves) from the number 1 to 100. So the text looks like:

 Hello my name is Dave, I am from California an I like fishing.

Any help on creating a regex that can do this?

Thanks

The regex:

\[([1-9]\d?|100)\]

will match any number, from 1 to 100 (both inclusive), inside square brackets.

So, you simply search for that pattern using your regex-tool or programming language (I don't know what you're using) and replace those with an empty string.

HTH

Thanks for the help. I am staring at it and I still can't decipher it.

People that are amazed of programmers, well programmers should be amazed of regex experts.

 Thanks!

specmav:

Thanks for the help. I am staring at it and I still can't decipher it.

People that are amazed of programmers, well programmers should be amazed of regex experts.

 Thanks!

You're most welcome.

Here's an explanation:

\[         // matches an opening square bracket
(          // open group 1
  [1-9]    // matches '1', '2', '3', '4', '5', '6', '7', '8' or '9'
  \d?      // _optionally_ matches '1', '2', '3', '4', '5', '6', '7', '8', '9' or '0'
  |        // OR
  100      // matches '100'
)          // close group 1
\]

So in plain English: "Match '[', followed by any number except '0' optionally followed by any number, or, '100', and finally, ending with ']'".

Note that without the parenthesis, \[[1-9]\d?|100\],

\[[1-9]\d? // the first part
|          // OR
100\]      // the second part

... it would match only the first OR the second part. So numbers with a '[' in front of it or with a ']' at the end would match, but not numbers with both '[' and ']'!