Hi Iam trying to build a regex to allow 0-9 and A-Z (Capitalised) with a string length of 18 characters and have the following code:

^([A-Z0-9]){18}

However I need to allow "spaces" "ampersands" "hyphens" "full Stops" and "forward slash" 

Please could someone advise on how these characters can also be added

Many thanks in anticipation

Rgds

Colin 

 

I am also not a expert in RegEx, but I guess I know the solution for your issue.

Try with this, simple mistake :-), 

^([A-Z]|[0-9]){18}

it should check for characters and digits, if you want to include more special characters to allow, attach to the same string with the pipeline "|" mark. Your expr.. also may work, but you can keep it clean by having seperators like above.

You may check for special chars syntax to represent in expression in the following,

 http----//www----devguru----com/Technologies/ecmaScript/quickref/regexp_special_characters.html

If you want to allow a space then it's "\s", (you can find more in the above), the expression will be like

^([A-Z]|[0-9]|[\s]){18}

 

 hope this would help you understand about regex...

 

Thanks, 

Chinthana

 

Hi Chinthana,

Thanks for your reply.

I tried

^([A-Z]|[0-9]|[ ]||[-]|[.]|[/]){18}

but it did not allow either numeric or special charcters

Any Suggestions?

Rgds

Colin

 

^([A-Z]|[0-9]|[\s]){18}

 Well... you can validate the expression in http----//www---fileformat--info/tool/regex.htm

It should work. Note that your character limit is set to 18.

 

It's all I can do for now.

 

Thanks,

Chinthana 

 

I have adjusted the regex to

^([A-Z]|[0-9]|[\s]|[/]){1,18}

and this will alow A-Z 1-9 space and / as the first character of the string subsequent characters can be lowercase or other special characters.

I need to allow only capitals throughout the string and only those special characters that I have specified

Rgds

Colin

 

colinejarvis:

Hi Iam trying to build a regex to allow 0-9 and A-Z (Capitalised) with a string length of 18 characters

However I need to allow "spaces" "ampersands" "hyphens" "full Stops" and "forward slash" 

^[A-Z0-9 &./-]{18}$

---

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chinthana:

I am also not a expert in RegEx, but I guess I know the solution for your issue.

Try with this, simple mistake :-), 

^([A-Z]|[0-9]){18}

it should check for characters and digits, if you want to include more special characters to allow, attach to the same string with the pipeline "|" mark. Your expr.. also may work, but you can keep it clean by having seperators like above.

You may check for special chars syntax to represent in expression in the following,

 http----//www----devguru----com/Technologies/ecmaScript/quickref/regexp_special_characters.html

If you want to allow a space then it's "\s", (you can find more in the above), the expression will be like

^([A-Z]|[0-9]|[\s]){18}

 

 hope this would help you understand about regex...

 

Thanks, 

Chinthana

 

You do not appear to have a clear grasp of the Character Class.

Using alternation isn't need in this case. It not wrong just unnecessarily verbose  As ddrurik demonstrated you only need to add the desired characters to the character class. 

http://regexadvice.com/blogs/mash/archive/2008/01/31/A-touch-of-Character-Class.aspx

Also \s doesn't just match a space. So you are overmatching the requirements 

---

Michael

"In theory, theory and practice are the same. In practice, they are not."
Albert Einstein

Many thanks for your help.

Looking at the answer increases my understanding on the fly and you help is much appreciated

Kind regards

 Colin